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3 bar map sensor


will15
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Iff that data is correct then that can be done.

First convert the kPa to inHg by multiplying it by 0.2953

11 kPa= 3.4283 inHg,  307 kPa= 90.657 inHg

Ford uses MAP = Volts * Slope - Offset.

so 90.657 = 4.75 * Slope - Offset (1)

and 3.483 = 0.25 * Slope - Offset (2)

Subtract equation (2) from equation (1)

87.174 = 4.5 Slope

19.372 = Slope.

Substituting back gives

90.657 = 4.75 * 19.372 - Offset

-1.36 = Offset, => Offset = 1.36 

Edited by Darryl@pcmtec
Change KPH to KPA
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On 10/7/2020 at 12:36 PM, Darryl@pcmtec said:

Sam, I just rechecked and 11 kpa is 3.2483 like you said. Pressure differential would be 87.409 => Slope 19.424, back feeding and Offset => 1.607

Good spotting.

Just Confirming the units is inHg and that auF0037 is 19.424 & auF0038 is 1.607

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18 hours ago, JMSMotorsport said:

Just Confirming the units is inHg and that auF0037 is 19.424 & auF0038 is 1.607

The standard units are inHG. Turbo and non turbo offsets are inverted. One is negative, I don't know why Ford did that but make sure you use the correct value if you are using turbo logic enabled or not.

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53 minutes ago, Roland@pcmtec said:

The standard units are inHG. Turbo and non turbo offsets are inverted. One is negative, I don't know why Ford did that but make sure you use the correct value if you are using turbo logic enabled or not.

Factory BF Mk2 Turbo

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